获取实现最短距离的点

xieqling

我用CATDistanceMinBodyBody接口的GetDistance()来获取两直线之间的最短距离，然后我想获得实现这最短距离的两个点，我用的是GetPoints( CATPoint*&  oPoint1, CATPoint*& oPoint2) ，但结果oPoint1和oPoint2是空的，我想请问这是为什么呀？直线的类型是GSMLine。具体代码如下：
CATISpecObject_var TheLine1 = pIDescendantOnOpenBody1->GetChildAtPosition(1);
CATISpecObject_var TheLine2 = pIDescendantOnOpenBody1->GetChildAtPosition(14);

CATGeoFactory* pGeomFactory = ::CATCreateCGMContainer();
  CATSoftwareConfiguration *pConfig = NULL;
  pConfig = new CATSoftwareConfiguration();
  CATCGMJournalList *pJournal = NULL;
  pJournal = new CATCGMJournalList();
  CATTopData* pTopoData = NULL;
  pTopoData = new CATTopData(pConfig,pJournal);

CATIGeometricalElement_var spGeoLine1 = TheLine1;
CATIGeometricalElement_var spGeoLine2 = TheLine2;
CATBody* pBodyLine1 = spGeoLine1->GetBodyResult();
CATBody* pBodyLine2 = spGeoLine2->GetBodyResult();
if(pBodyLine1 == NULL || pBodyLine2 == NULL)
  {
          cout<<"Error in Inputs !"<<endl;
  }
  CATDistanceMinBodyBody *pDistanceMinMin = NULL;
  pDistanceMinMin = CATCreateDistanceMinTopo(pGeomFactory,pTopoData,pBodyLine1,pBodyLine2,BASIC);
  double totallength = 0.0;
  totallength = pDistanceMinMin->GetDistance(); //得出最短距离
  cout << "totallength   "<< totallength << endl;

CATPoint *oPoint1 = NULL;
  CATPoint *oPoint2 = NULL;
  pDistanceMinMin -> GetPoints(oPoint1,oPoint2);//获取实现最短距离的两个点
  if (NULL == oPoint1)
  {
          cout<<"oPoint1为空"<<endl;
  }
  cout << "The X cordinate is :" << oPoint1 -> GetX() << endl;
最短距离能够正确得到，但输出oPoint1为空。

圈圈眉

圈圈眉

zheng.lei213@16

xieqling

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xieqling

xieqling

linlily0925

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