iCAx开思工具箱

标题: 向zzz版主大哥请教个曲线相交得交点的问题 [打印本页]

作者: rafaleb01 时间: 2008-4-8 14:22
标题: 向zzz版主大哥请教个曲线相交得交点的问题
ZZZ和各位版主，各位学长很不好意思现在还因为这么简单的问题打扰大家，但小弟试了很多次了就是得不到结果，在建立好的模型上做条截面线，然后哦求得2截面线的交点，截面线我做出来了但交点始终得不到，请ZZZ大哥和其他各位学长帮我看看，感激不尽
void ufusr(char *param, int *retcode, int param_len)
{
  if (!UF_CALL(UF_initialize()))
  {
//////////////////////////////////////////////////////////获得当前叶object_id

  int          type1,subtype;
  tag_t          part_tag;
  tag_t          block_tag;
  tag_t          plane1_tag;

  part_tag=UF_PART_ask_display_part();

  block_tag=NULL_TAG;

  UF_OBJ_cycle_objs_in_part(part_tag,UF_solid_type,&block_tag);

  while (block_tag)
  {
   UF_OBJ_ask_type_and_subtype(block_tag,&type1,&subtype);
  if (subtype==UF_solid_body_subtype)
  {
   break;
  }
  UF_OBJ_cycle_objs_in_part(part_tag,UF_solid_type,&block_tag);
  }
////////////////第一条截面线
double  origin1_point[3];
double  pl1_normal[3];

  origin1_point[0] = 20.0;
  origin1_point[1] = 40.0;
  origin1_point[2] = 0;

  pl1_normal[0] = 0.0;
  pl1_normal[1] = 0.0;
  pl1_normal[2] = 1.0;


UF_MODL_create_plane(origin1_point, pl1_normal, &plane1_tag);

tag_t  objects1[1];
tag_t  planes1[100];

objects1[0]=block_tag;


tag_t section_curves_feature1;
UF_CURVE_section_general_data_t  general1_data;
UF_CURVE_section_planes_data_t planes1_data;

planes1[0] = plane1_tag;
general1_data.associate    = 1;
general1_data.objects    = objects1;
general1_data.num_objects = 1;
general1_data.grouping    = 0;
general1_data.join_type    = 0;
general1_data.tolerance    = 0.0245;

planes1_data.planes       = planes1;
planes1_data.num_planes    = 1;

UF_CURVE_section_from_planes (&general1_data, &planes1_data,
               &section_curves_feature1);

double  origin2_point[3];
double  pl2_normal[3];

  origin2_point[0] = 20.0;
  origin2_point[1] = 0;
  origin2_point[2] = 40.0;

  pl2_normal[0] = 0.0;
  pl2_normal[1] = 1.0;
  pl2_normal[2] = 0.0;

//////////////////////第二截面线
  tag_t plane2_tag;
UF_MODL_create_plane(origin2_point, pl2_normal, &plane2_tag);

tag_t  objects2[1];
tag_t  planes2[100];

objects2[0]=block_tag;


tag_t section_curves_feature2;
UF_CURVE_section_general_data_t  general2_data;
UF_CURVE_section_planes_data_t planes2_data;

planes2[0] = plane2_tag;
general2_data.associate    = 1;
general2_data.objects    = objects2;
general2_data.num_objects = 1;
general2_data.grouping    = 0;
general2_data.join_type    = 0;
general2_data.tolerance    = 0.0245;

planes2_data.planes       = planes2;
planes2_data.num_planes    = 1;

UF_CURVE_section_from_planes (&general2_data, &planes2_data,
               &section_curves_feature2);

////////////////////求交
  int num_intersects, type;
  UF_MODL_intersect_info_p_t *intersect_data;

double tol = 0.1;

UF_MODL_intersect_objects(section_curves_feature2,section_curves_feature1,
   tol,&num_intersects,&intersect_data);
红色部分是不是有错误？
FILE *fp4;

if((fp4=fopen("e:\\my_source\\line4.txt","w"))==NULL)
{
      printf("could not open data file.");
      exit(0);
}

int i;
  for(i = 0; i < num_intersects; i++)
  {
type = (intersect_data)->intersect_type;

switch(type)
{
   case UF_MODL_INTERSECT_POINT:

      fprintf(fp4,"\nx,y,z coordinates are: (%f, %f, %f)\n",
            (intersect_data)->intersect.point.coords[0],
            (intersect_data)->intersect.point.coords[1],
            (intersect_data)->intersect.point.coords[2]);

      fprintf(fp4,"Object 1 UV parameters are: (%f, %f)\n",
            (intersect_data)->intersect.point.object_1_u_parm,
            (intersect_data)->intersect.point.object_1_v_parm);

      fprintf(fp4,"Object 2 UV parameters are: (%f, %f)\n",
            (intersect_data)->intersect.point.object_2_u_parm,
            (intersect_data)->intersect.point.object_2_v_parm);

      break;

   case UF_MODL_INTERSECT_COINCIDE:

      printf("\nCoincident curve tag is: %d\n",
            intersect_data->intersect.coincide.identifier);

      printf("Object 1 UV parameters are: (%f, %f)\n",
            intersect_data->intersect.coincide.object_1_first_parm,
            intersect_data->intersect.coincide.object_1_second_parm);

      printf("Object 2 UV parameters are: (%f, %f)\n",
            intersect_data->intersect.coincide.object_2_first_parm,
            intersect_data->intersect.coincide.object_2_second_parm);
      break;

   case UF_MODL_INTERSECT_CURVE:

      printf("\nThe curve identifier is: %d\n",
            (intersect_data)->intersect.curve.identifier);
      break;

   default:

      printf("\nSomething went wrong, we shouldn't be here!");
      break;
}

// Free each element of the array.
   UF_free(intersect_data);
  }

  if(num_intersects != 0)
  {
  //// Free the array.
UF_free(intersect_data);
  }

UF_CALL(UF_terminate());
  }
}

int ufusr_ask_unload(void)
{
  return (UF_UNLOAD_IMMEDIATELY);
}
作者: zzz 时间: 2008-4-9 22:47
feature和feature求交，NX不能做吧
作者: rafaleb01 时间: 2008-4-11 14:29
那怎么才能实现目的呢?
作者: zzz 时间: 2008-4-11 20:24
用UF_MODL_ask_feat_objects可以问出两个section特征中的曲线，然后用曲线求交点
作者: rafaleb01 时间: 2008-4-15 08:36
恩谢谢版主  我去试试看
作者: rafaleb01 时间: 2008-4-15 09:37
zzz大哥针对上面的球形用您给的函数我做出来了
但针对另一个零件却做不出来
平面与体相交得出的 4条线中我都试过了都报和第一条曲线没有交点
作者: rafaleb01 时间: 2008-4-15 10:10
还有 UF_CURVE_ask_feature_curves  输出的为
  num_section_curves2 is  4
section_curves2 is  19069
section_curves2 is  19070
section_curves2 is  19067
section_curves2 is  19068
UF_MODL_ask_feat_objects 得到的是
eiids2——num is  4
eiids2 is  19070
eiids2 is  19068
eiids2 is  19069
eiids2 is  19067
这两个函数得到的值基本一致，是不是可以相互替换啊?
作者: rafaleb01 时间: 2008-4-15 10:28
eids is  1
eiids[0] is  19066
eiids2 is  4
eiids2[0] is  19008
eiids2[1] is  19070
eiids2[2] is  19071
eiids2[3] is  19069

UF_MODL_intersect_objects(eiids2[0],eiids[0],tol,&num_intersects1,&intersect_1data);
UF_MODL_intersect_objects(eiids2[1],eiids[0],tol,&num_intersects2,&intersect_2data);
UF_MODL_intersect_objects(eiids2[2],eiids[0],tol,&num_intersects3,&intersect_3data);
UF_MODL_intersect_objects(eiids2[3],eiids[0],tol,&num_intersects4,&intersect_4data);

num_intersects1 are: 0
num_intersects2 are: 0
num_intersects3 are: 0
num_intersects4 are: 0
怎么会没有交点呢？？
作者: zzz 时间: 2008-4-15 11:13
先在NX里面试一下，能不能选到两条线的交点，如果可以，说明你的代码有问题，如果不行，就说明确实没有交点。
作者: rafaleb01 时间: 2008-4-15 11:14
试了几个这个函数似乎不适合样条曲线和样条曲线相交就点
作者: zzz 时间: 2008-4-15 11:18
你给的tol是多少？
作者: zzz 时间: 2008-4-15 11:19

原帖由  于 2008-4-15 10:10 发表
还有 UF_CURVE_ask_feature_curves  输出的为
  num_section_curves2 is  4
section_curves2 is  19069
section_curves2 is  19070
section_curves2 is  19067
section_curves2 is  19068
UF_MODL_ask_ ...

可以
作者: rafaleb01 时间: 2008-4-15 11:25

原贴由发表：
先在NX里面试一下，能不能选到两条线的交点，如果可以，说明你的代码有问题，如果不行，就说明确实没有交点。

交互下选择插入点，捕捉项选择交点确实看到捕捉到了2条交点
代码对圆柱体和椭圆柱体圆球都有用就是对通过曲线组拉出来的体没有效果
作者: rafaleb01 时间: 2008-4-15 14:14
tol 试过.0001 .001 .01 1 10.0 好像都没有结果
作者: zzz 时间: 2008-4-15 14:33

原帖由  于 2008-4-15 10:28 发表
eids is  1
eiids is  19066
eiids2 is  4
eiids2 is  19008
eiids2 is  19070
eiids2 is  19071
eiids2 is  19069

UF_MODL_intersect_objects(eiids2,eiids,tol,&num_intersects1,&inter ...

你看一下自己的代码，在求交时第二个参数总是eiids[0]，如果eiids[0]位于头部的话，肯定是没有交点的。
作者: rafaleb01 时间: 2008-4-15 14:47
ZZZ 大哥真是太崇拜你了是公差的问题 UF_CURVE_section_from_planes 处的截线公差 api帮助文档里给的过大造成的
真是麻烦您了
再次感谢

欢迎光临 iCAx开思工具箱 (https://t.icax.org/) Powered by Discuz! X3.3