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标题: 【求助】一个基准面和一个圆柱面的交线如何求？ [打印本页]

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作者: tari    时间: 2004-7-2 21:33
标题: 【求助】一个基准面和一个圆柱面的交线如何求？
使用UF_MODL_intersect_objects（）？
如果是的话，得到intersections后如何得到curve?

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作者: tari    时间: 2004-7-2 22:10
UF_MODL_intersect_objects(plane,p2->eid,tolerance,[$num_intersections,&intersections)]
     bcurve=((*intersections)->intersect).curve.identifier;
我已经通过这种方法得到封闭圆环，但是现在我想通过bcurve生成一个以它为边界的平面，UF_MODL_create_bplane（）好像需要的类型是UF_STRING_p_t ，而这里bcurve的类型是tag_t，怎么样才能得到呢？
下面是我赋的值，但调试到这里就出错，不知是什么问题？
section->dir[0]=1;
section->id[0]=bcurve;
section->string[0]=1;
  

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作者: wflying    时间: 2004-7-3 08:56
我刚刚用过这个，给你个例子：
#include <stdio.h>
#include <uf_modl.h>
#include <uf.h>
#include <uf_obj.h>
#include <uf_curve.h>
#include <uf_defs.h>
#include <uf_csys.h>
#define UF_CALL(X) (report( __FILE__, __LINE__, #X, (X)))
static void get_intersect(tag_t curve, tag_t face, double tol);
static int report( char *file, int line, char *call, int irc)
{
  if (irc)
  {
     char    messg[133];
  
     printf("%s, line %d:  %s\n", file, line, call);
  
     (UF_get_fail_message(irc, messg)) ?
       printf("    returned a %d\n", irc) :
       printf("    returned error %d:  %s\n", irc, messg);
  }
  return(irc);
}
static void do_ugopen_api(void)
{
  tag_t base_sheet_id, line_id;
  tag_t face, arc_tag, line2_id;
  
  int num_pole_u = 4;
  int num_pole_v = 4;
  int u_ord = 4;
  int v_ord = 4;
  int knot_fix;
  int pole_fix;
  
  int i, j, k = 0;
  UF_CURVE_line_t line_coords  = {1.5,1.5,-2,1.5,1.5,1.0};
  UF_CURVE_line_t line_coords2 = {0.0, 3.0, 0.0};
  UF_CURVE_arc_t arc_coords = {NULL_TAG,0.0,180*DEGRA,1.5,0.0,-1.5,0.25};
  
  uf_list_p_t list;
  
  double weight = 1.0;
  double u_knot[9] = {0.0,0.0,0.0,0.0,1.0,1.0,1.0,1.0,1.0};
  double v_knot[9] = {0.0,0.0,0.0,0.0,1.0,1.0,1.0,1.0,1.0};
  double pole[64];
  
  double tol = .001;
  
  double matrix_values[9] = {1.0, 0.0, 0.0,
                             0.0, 0.0, 1.0,
                             0.0, 1.0, 0.0};
  
  /* Create pole array data. */
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      pole[k++] = i;
      pole[k++] = j;
      pole[k++] = 0.0;
      pole[k++] = weight;
    }
  }
  /* Create base surface. */
  UF_CALL(UF_MODL_create_bsurf(num_pole_u, num_pole_v, u_ord, v_ord,
                               u_knot, v_knot,pole,&base_sheet_id,
                               [$knot_fix,&pole_fix))]
  
  /* Get faces. */
  UF_CALL(UF_MODL_ask_body_faces(base_sheet_id,[$list))]
  UF_CALL(UF_MODL_ask_list_item(list,0,[$face))]
  UF_CALL(UF_MODL_delete_list([$list))]
  
  /* Create line. */
  UF_CALL(UF_CURVE_create_line([$line_coords,&line_id))]
  
  /* Get line intersection. */
  get_intersect(line_id, face, tol);
   
  /* Create coincident line. */
  UF_CALL(UF_CURVE_create_line([$line_coords2,&line2_id))]
  UF_CALL(UF_OBJ_set_color(line2_id, UF_OBJ_YELLOW));
  
  /* Get coincident line intersection data */
  get_intersect(line2_id, face, tol);
  
  /* Create arc. */
  UF_CALL(UF_CSYS_create_matrix(matrix_values,[$arc_coords.matrix_tag))]
  UF_CALL(UF_CURVE_create_arc([$arc_coords, &arc_tag))]
  
  /* Get arc intersection. */
  get_intersect(arc_tag, face, tol);
}
/*ARGSUSED*/
void ufusr(char *param, int *retcode, int param_len)
{
  if (!UF_CALL(UF_initialize()))
  {
    do_ugopen_api();
    UF_CALL(UF_terminate());
  }
}
int ufusr_ask_unload(void)
{
  return (UF_UNLOAD_IMMEDIATELY);
}
static void get_intersect(tag_t curve, tag_t face, double tol)
{
  int num_intersects, type, i;
  UF_MODL_intersect_info_p_t *intersect_data;
  
  UF_CALL(UF_MODL_intersect_objects(curve,face,tol,[$num_intersects,&intersect_data))]
  
  printf("\n Number of intersections = %d\n", num_intersects);
  
  for(i = 0; i < num_intersects; i++)
  {
    type = (intersect_data)->intersect_type;
  
    switch(type)
    {
      case UF_MODL_INTERSECT_POINT:
  
        printf("\nx,y,z coordinates are: (%f, %f, %f)\n",
               (intersect_data)->intersect.point.coords[0],
               (intersect_data)->intersect.point.coords[1],
               (intersect_data)->intersect.point.coords[2]);
  
        printf("Object 1 UV parameters are: (%f, %f)\n",
               (intersect_data)->intersect.point.object_1_u_parm,
               (intersect_data)->intersect.point.object_1_v_parm);
  
        printf("Object 2 UV parameters are: (%f, %f)\n",
               (intersect_data)->intersect.point.object_2_u_parm,
               (intersect_data)->intersect.point.object_2_v_parm);
  
        break;
   
      case UF_MODL_INTERSECT_COINCIDE:
  
        printf("\nCoincident curve tag is: %d\n",
               intersect_data->intersect.coincide.identifier);
  
        printf("Object 1 UV parameters are: (%f, %f)\n",
               intersect_data->intersect.coincide.object_1_first_parm,
               intersect_data->intersect.coincide.object_1_second_parm);
  
        printf("Object 2 UV parameters are: (%f, %f)\n",
               intersect_data->intersect.coincide.object_2_first_parm,
               intersect_data->intersect.coincide.object_2_second_parm);
        break;
  
      case UF_MODL_INTERSECT_CURVE:
  
        printf("\nThe curve identifier is: %d\n",
               (intersect_data)->intersect.curve.identifier);
        break;
  
      default:
  
        printf("\nSomething went wrong, we shouldn't be here!");
        break;
    }
  
    /* Free each element of the array. */
      UF_free(intersect_data);
  }
  
  if(num_intersects != 0)
  {
    /* Free the array. */
    UF_free(intersect_data);
  }
}

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作者: tari    时间: 2004-7-3 09:06
谢谢楼上的Wflying兄！
不过我现在需要知道的是如何根据封闭平面相交线创建有界平面

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作者: tari    时间: 2004-7-4 13:21
这个我已经解决，谢谢大家！

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