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标题: 【求助】如何实现螺纹 [打印本页]

作者: haiying 时间: 2004-5-24 09:49
标题: 【求助】如何实现螺纹
在一个圆柱体的两端生成螺纹程序如下：
//建左端螺纹
  tag_t face, s_face, c_face ,feature_eid;
   double point[3], dir[3], box[6], radius, rad;
int i, num, type, sen;
UF_MODL_symb_thread_data_t thread;
// Get cylinder feature faces
  UF_MODL_ask_feat_faces(d1_id,[$list)]
UF_MODL_ask_list_count(list,[$num)]
for (i=0;i<num;i++)
{
   UF_CALL(UF_MODL_ask_list_item(list,i,[$face))]

   UF_CALL(UF_MODL_ask_face_data(face,&type,point,dir,box,
                              [$radius,&rad,&sen))]
   if (type == 22) /* Planar face */
s_face = face;
   if (type == 16) /* Cylindrical face */
   c_face = face;
}
UF_MODL_delete_list([$list)]
/*
Create symbolic thread
*/
thread.cyl_face = c_face;
thread.start_face = s_face;
thread.axis_direction[0]=0;
thread.axis_direction[1]=0;
thread.axis_direction[2]=1;
thread.include_instances = UF_MODL_INCL_INSTANCES;
thread.rotation=UF_MODL_RIGHT_HAND;
thread.length_flag=UF_MODL_FIXED_LENGTH;
thread.tapered = UF_MODL_NON_TAPERED;
thread.num_starts = 1;
thread.length="20";
thread.form = "Metric";
thread.method = "CUT";
thread.callout = "M20_X_1";
thread.major_dia = "20";
thread.minor_dia = "18.981";
thread.tapped_dia = "19.794";
thread.pitch = "1";
thread.angle = "60";
UF_CALL(UF_MODL_create_symb_thread([$thread, &feature_eid))]
  if(!UF_CALL(UF_MODL_ask_symb_thread_parms(feature_eid, &thread)))
{
//  Print data
   printf("Cylindrical face tag = %d\n", thread.cyl_face);
   printf("Start face tag = %d\n", thread.start_face);
   printf("Thread axis direction = (%f,%f,%f)\n",
   thread.axis_direction[0],thread.axis_direction[1],
   thread.axis_direction[2]);
   printf("Number of starts = %d\n", thread.num_starts);
   if (thread.include_instances == UF_MODL_INCL_INSTANCES)
   printf("Include instances = Yes\n");
   else
   printf("Include instances = No\n");
   if (thread.rotation == UF_MODL_RIGHT_HAND)
   printf("Rotation = Right_hand\n");
   else
   printf("Rotation = Left_hand\n");
   if (thread.length_flag == UF_MODL_FIXED_LENGTH)
   printf("Thread length flag = Fixed length\n");
   else
   printf("Thread length flag = Full thread\n");
   if (thread.tapered == UF_MODL_TAPERED)
   printf("Thread tapered = Yes\n");
   else
   printf("Thread tapered = No\n");
   printf("Length expression %s\n", thread.length);
   printf("Form = %s\n", thread.form);
   printf("Callout = %s\n", thread.callout);
   printf("Method = %s\n", thread.method);
   printf("Major diameter expression %s\n", thread.major_dia);
   printf("Minor diameter expression %s\n", thread.minor_dia);
   printf("Tapped diameter expression %s\n", thread.tapped_dia);
   printf("

itch expression %s\n", thread.pitch);
printf("Angle expression %s\n", thread.angle);
}
UF_free(thread.length);
UF_free(thread.form);
UF_free(thread.method);
UF_free(thread.callout);
UF_free(thread.major_dia);
UF_free(thread.minor_dia);
UF_free(thread.tapped_dia);
UF_free(thread.pitch);
UF_free(thread.angle);
}
可以实现

可是同样的在右端
//建右端螺纹
tag_t face1, s_face1, c_face1 ,feature_eid1;
  uf_list_p_t list1;
double point1[3], dir1[3], box1[6], radius1, rad1;
int i1, num1, type1, sen1;

UF_MODL_symb_thread_data_t thread1;
// Get cylinder feature faces

UF_MODL_ask_feat_faces(dd_id,[$list1)]
  UF_MODL_ask_list_count(list1,[$num1)]
for (i1=0;i1<num1;i1++)
{
   UF_CALL(UF_MODL_ask_list_item(list1,i1,[$face1))]

   UF_CALL(UF_MODL_ask_face_data(face1,&type1,point1,dir1,box1,
                              [$radius1,&rad1,&sen1))]
   if (type1 == 22) /* Planar face */
s_face1 = face1;
if (type1 == 16) /* Cylindrical face */
c_face1 = face1;
  }
UF_MODL_delete_list([$list1)]*/

/*  Create symbolic thread*/

thread1.cyl_face = c_face1;
thread1.start_face = s_face1;
thread1.axis_direction[0]=0;
thread1.axis_direction[1]=0;
thread1.axis_direction[2]=-1;
thread1.include_instances = UF_MODL_INCL_INSTANCES;
thread1.rotation=UF_MODL_RIGHT_HAND;
thread1.length_flag=UF_MODL_FIXED_LENGTH;
thread1.tapered = UF_MODL_NON_TAPERED;
thread1.num_starts = 1;
thread1.length="20";
thread1.form = "Metric";
thread1.method = "CUT";
thread1.callout = "M20_X_1";
thread1.major_dia = "20";
thread1.minor_dia = "18.981";
thread1.tapped_dia = "19.794";
thread1.pitch = "1";
thread1.angle = "60";
UF_CALL(UF_MODL_create_symb_thread([$thread1, &feature_eid1))]*/
  // Retrieve datahao le ,hao
  if(!UF_CALL(UF_MODL_ask_symb_thread_parms(feature_eid1, &thread1)))
{
//  Print data
   printf("Cylindrical face tag = %d\n", thread1.cyl_face);
   printf("Start face tag = %d\n", thread1.start_face);
   printf("Thread axis direction = (%f,%f,%f)\n",
   thread1.axis_direction[0],thread1.axis_direction[1],
   thread1.axis_direction[2]);
   printf("Number of starts = %d\n", thread1.num_starts);
   if (thread1.include_instances == UF_MODL_INCL_INSTANCES)
   printf("Include instances = Yes\n");
   else
   printf("Include instances = No\n");
   if (thread1.rotation == UF_MODL_RIGHT_HAND)
   printf("Rotation = Right_hand\n");
   else
   printf("Rotation = Left_hand\n");
   if (thread1.length_flag == UF_MODL_FIXED_LENGTH)
   printf("Thread length flag = Fixed length\n");
   else
   printf("Thread length flag = Full thread\n");
   if (thread1.tapered == UF_MODL_TAPERED)
   printf("Thread tapered = Yes\n");
   else
   printf("Thread tapered = No\n");
   printf("Length expression %s\n", thread1.length);
   printf("Form = %s\n", thread1.form);
   printf("Callout = %s\n", thread1.callout);
   printf("Method = %s\n", thread1.method);
   printf("Major diameter expression %s\n", thread1.major_dia);
   printf("Minor diameter expression %s\n", thread1.minor_dia);
   printf("Tapped diameter expression %s\n", thread1.tapped_dia);
   printf("

itch expression %s\n", thread1.pitch);
printf("Angle expression %s\n", thread1.angle);
}
UF_free(thread1.length);
UF_free(thread1.form);
UF_free(thread1.method);
UF_free(thread1.callout);
UF_free(thread1.major_dia);
UF_free(thread1.minor_dia);
UF_free(thread1.tapped_dia);
UF_free(thread1.pitch);
UF_free(thread1.angle);
}
却实现不了！

两端的程序是一样的！只是改了个变量而已!为什么不行呢？
请版主和各位高手指教！

作者: liberty000 时间: 2004-5-24 12:18
thread1.start_face 找错了吧，type==22的面圆柱上有2个，你找哪个？

作者: haiying 时间: 2004-5-24 15:29
谢谢liberty000!
那左端的螺纹为什么可以实现？type==22的面圆柱上虽有两个，可是它是否可以根据 thread1.axis_direction[0]=0;
          thread1.axis_direction[1]=0;
         thread1.axis_direction[2]=-1;
来判断出该在那个平面上呢？
我编译时会出现好多的错误!
实在搞不懂！还望指教！

作者: liberty000 时间: 2004-5-24 17:18
利用平面的法线方向判断！

作者: haiying 时间: 2004-5-24 19:35
那具体要用到那个函数呢？

作者: bigban 时间: 2008-2-26 13:12
学习了,谢谢!!!

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